Get node attribute xml C#

I am trying to get all the nodes from an xml file, but I cannot get the node having attributes such as Home and Work. Well, in my case I can get phone Home but not phone Work. Thank you.

This is the xml file structure:

<Employees>
    <Employee>
      <EmpId>1</EmpId>
      <Name>Sam</Name>   
      <Sex>Male</Sex>
      <Phone Type="Home">423-555-0124</Phone>
      <Phone Type="Work">424-555-0545</Phone>
      <Address>
          <Street>7A Cox Street</Street>
          <City>Acampo</City>
          <State>CA</State>
          <Zip>95220</Zip>
          <Country>USA</Country>
      </Address>
    </Employee>
</Employee>

This is my code in C#:

XElement xelement = XElement.Load("employees.xml");
IEnumerable<XElement> employees = xelement.Elements();
Console.WriteLine("List of all Employee Names along with their ID:");
foreach (var employee in employees)
{     
   employee.Element("EmpId").Value);
   Console.WriteLine("SEX: {0}", employee.Element("Sex").Value);
   Console.WriteLine("Home: {0}", employee.Element("Phone").Value);
   Console.WriteLine("Work: {0}\n", employee.Element("Phone").Value);
}

Result:

enter image description here

Wished:

enter image description here

Jon Skeet
people
quotationmark

You need to use the Attribute method to get at an attribute. You'll need to query for Phone elements with a Type attribute of Home. For example:

Console.WriteLine("Home: {0}",
    employee.Elements("Phone")
            .Single(x => x.Attribute("Type").Value == "Home")
            .Value);

You should think about what you want to do if there isn't a phone number for the type you want, or if there are multiple ones. (The Single method requires exactly one match. There's also First and Last, as well as FirstOrDefault or LastOrDefault, which will return null if there are no matches.)

people

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