"The system cannot find the file specified" error on process.Start();

I am trying to get the process respond as a string so I can use it in different place in my code, this is the solution that I have so far:

const string ex1 = @"C:\Projects\MyProgram.exe ";
      const string ex2 = @"C:\Projects\ProgramXmlConfig.xml";


      Process process = new Process();
      process.StartInfo.WorkingDirectory = @"C:\Projects";
      process.StartInfo.FileName = "MyProgram.exe ";
      process.StartInfo.Arguments = ex2;
      process.StartInfo.Password = new System.Security.SecureString();
      process.StartInfo.UseShellExecute = false;
      process.StartInfo.RedirectStandardOutput = true;  

      try
      {
          process.Start();
          StreamReader reader = process.StandardOutput;
          string output = reader.ReadToEnd();
      }
      catch (Exception exception)
      {
          AddComment(exception.ToString());
      }

But when I'm running this I get:

"The system cannot find the file specified" error in process.Start(); without 
      process.StartInfo.UseShellExecute = false;
      process.StartInfo.RedirectStandardOutput = true;

The code runs fine but it just open console window and all the process response is trow there so I can't use it as string.

Does anyone know why I am getting this error or maybe a different solution to my problem?

Jon Skeet
people
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I suspect the problem is that the filename you're specifying is relative to your working directory, and you're expecting Process.Start to look there when starting the process - I don't believe it works that way when UseShellExecute is false. Try just specifying the absolute filename of the process you want to start:

process.StartInfo.FileName = @"C:\Projects\MyProgram.exe";

Note that I've also removed the space from the end of the string you were assigning for the FileName property - it's entirely possible that was casuing the problem too.

people

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